[source]
| wk | = a3akabbkb2 |
| = ak+4bk+3 | |
(a) Choose w = ambm+1cm+2
(b) Choose w = ambmbmamambm = amb2ma2mbm
(c) Choose w = ambmambm
(d) Choose w = a2m+1b2ma2m+1b2m
(e) Choose w = ambm#ambm
(f) Choose w = am!
wo = am!-j for some 0 < j < m
For m > 2 we have
(m - 1)! < m((m - 1)! - 1) = m! - m < m! - j < m! - 1 < m!
Thus
(m - 1)! < |wo| < m! for m > 2 and in such a case wo is not in L.
If m = 1 then w = a and w = uvxyz
vy = 1
w3 = a3 not in
L
If m = 2 then (w = aa and w = uvxyz
vy = a
w3 = a3 not in L) or (vy
= aa
w2 = a4 not in L)
L not cfl.
3.4.3 Choose (w1, w2) = (ambmcm, dm)
Consider any decomposition
w1 = u1v1x1y1z1
w2 = u2v2x2y2z2
If v2y2 =
then choose k = 0. In such a case
(u1v10x1y10z1, u2v20x2y20z2) = (am-j1bm-j2cm-j3, dm) with j1 > 0 or j2 > 0
or j3 > 0.
If v2y2 /=
then choose k = 2. In such a case
(u1v12x1y12z1, u2v22x2y22z2) = (am+j1bm+j2cm+j3, dm+j4) with j4 > 0 and
either j1 = 0 or j2 = 0 or j3 = 0.