Sketch of Solutions to Exercises

1.1.1
(a)
Unary alphabets
{a}, {b}, {c}
Binary alphabets
{a,b}, {b,a}, {a,c}, {c,a}, {b,c}, {c,b}
Other alphabets
{a,b,c}, {a,c,b}, {b,a,c}, {b,c,a}, {c,a,b}, {c,b,a}
(b)
Unary
t
Binary
t(t-1)

1.1.2

(a)
e, a, b, ab, ba
(b)
aaa, aab, aba, abb, baa, bab, bba, bbb

1.1.3

(a)
ab=aab, ba=aba, a2=aa, a0b2 =abab, a2b2e=aaabab
(b)
a = e, b=abb; a=a, b=bb; a=ab, b=b; a=abb, b = e

1.1.4

(a)
e, 0, 01, 011, 0110, 01101
(b)
e, 0, 1, 11, 111, 1111, 011110

1.1.5 rt

1.1.6

(a)
e, a, a2 a3, a4, a5, ..., a19
(b)
e, a, b, c, aa, ab, ac, ba, bb, bc, ca, cb, cc, aaa, aab, aac, aba, abb, abc, aca

1.1.7

(a)
S1 = {e, a, a2, a3, ..., at-1} hence S1  /~\ S2 = S1
(b)
|S2| = (1 string of length 0) + (3 string of length 1) + (9 string of length 2) + (27 string of length 3) + (81 string of length 4) + the following 3 strings of length 5: aaaaa, aaaab, aaaba; hence S1  /~\ S2 = e, a, a2, a3, a4, a5 .

1.1.8 A representation f of S* for the i’th element in the canonically ordered set S* can satisfy the following condition, according to the case.

(a)
f (e) = { the i’th element in the canonically ordered set {0,1}* }
(b)
f (e) = { the i’th element in the canonically ordered set {1}* }

1.1.9 i/j --> 1i01j

1.1.10 For a given binary representation f 1 take f 2(e) = {1i0|i > 0}f 1(e)

1.1.11

(a)
f (e) = {0}f 1(e)  U {1}f 2(e)
(b)
f (e) = {1|a|0ab|a in f 1(e), b in f 2(e)}
(c)
f (e) = {1|a1|0a11|a2|0a2...1|ak|0ak|k > 0, a1, ..., ak in f 1(e)}

1.1.12 Assume to the contrary the existence of a binary representation f. Denote by min{f (a)} the binary string which appears first in the canonical ordering of f (a) . Assume an ordering on the real numbers a1, a2, a3, ... such that ai precedes aj if and only if min{f (ai)} precedes min{f (aj)} in the canonical ordering of the binary strings. Then consider the real number a whose k’th digit is different from the k’th digit of ak for all k > 1. It follows that min{f (a)}, and hence f (a), is not defined for a.