CSE 321 Homework 20
Definition: Let f: integer≥0 --> integer≥0.
Then, O(f) = {t: integer≥0 --> integer≥0
where there are constants c > 0 and m ≥ 0 such that
t(n) ≤ c * f(n) for all n ≥ m}. When t is in O(f), we say t is O(f).
- Using the definition of O( ), prove: 9×n2 + 6×n + 3 is in O(n2).
- Using the definition of O( ), prove: 5×n×log2(n) + 4×n + 3×log2(n) + 2 is in O(n×log2n).
- In the following code segment, assume that
s and t are of type Array_Of_Integer with
lower bounds of 1 and with upper bounds of n, where
n is an integer greater than 1. Use O( )
notation to express the performance of the code segment as a
function of n. [Assume all array operations are implemented
in constant time.]
{
s[1] = t[1];
pos = 2;
while (pos <= t.Upper_Bound ())
{
s[pos] = s[pos-1] * t[pos] - 1;
pos++;
};
}